**TOPIC 8: LINEAR PROGRAMMING **

**Simultaneous Equations**

Simultaneous Equation from Word Problems

Form simultaneous equation from word problems

**LINEAR PROGRAMMING.**

Linear programming – is a branch of mathematics which deals with either minimizing the cost or maximizing the profit.

- It gives the best way of utilizing the scarce resources available.
- It is so called because it only involves equations and inequalities which are linear.

**Simultaneous Equation.**

One

of the methods used in solving linear simultaneous equations is a

graphical method. Two linear simultaneous equations in two unknowns can

be graphically solved by passing through the following procedures.

of the methods used in solving linear simultaneous equations is a

graphical method. Two linear simultaneous equations in two unknowns can

be graphically solved by passing through the following procedures.

- Draw

the two lines which represent the two equations on the xy – plane this

is done by deter mining at least two points through which each line

passes, the intercept are commonly used - Determine the point of intersection of the two lines. This point of intersection is the solution to the system of equations.

**FACT**:

- If two straight lines are not parallel then they meet at only one point:
- In case the lines do not meet, there is no solution to the corresponding system of simultaneous equations.

Example 1

Graphically solve the following system of simultaneous equations.

Example 2

Find the solution to the following system of simultaneous equations by graphical method.

Solving Simultaneous Equations Graphically

Solve simultaneous equations graphically

Example 3

Solve the following simultaneous equations graphically and check your solution by a non-graphical method:

Example 4

Find the solution to the following system of simultaneous equations by graphical method.

Exercise 1

Find the solution to the following systems of simultaneous equations graphically.

**:**

*Try*Ali paid 34 shillings for 10 oranges and 35 mangoes. Moshi went to the

same market and paid 24 shillings for 16 oranges and 18 mangoes. What

was the price for a mango and for an orange?

**Inequalities**

Forming Linear Inequalities in Two Unknowns from Word Problems

Form linear inequalities in two unknowns from word problems

**Linear inequalities**

- Normally any straight line drawn on xy – plane separates it into two disjoint sets. These sets are called
**half – planes** - Consider the equation y = 5 drawn on the xy plane as shown below.

From

the figure above, all points above the line, that is all points in the

half plane A which is above the line satisfy the relation y>5 and

those lying in the half plane B which is below the given line, satisfy

the relation y< 5.

the figure above, all points above the line, that is all points in the

half plane A which is above the line satisfy the relation y>5 and

those lying in the half plane B which is below the given line, satisfy

the relation y< 5.

**Shading of Regions**

- In linear programming usually the region of interest is left clear that is we shade unwanted region(s).

*NB**:*

When

shading the half planes we consider the inequalities as the equations

but dotted lines are used for the relations with > or < signs and

normal lines are used for those with ≥ or ≤ signs.

shading the half planes we consider the inequalities as the equations

but dotted lines are used for the relations with > or < signs and

normal lines are used for those with ≥ or ≤ signs.

Consider

the inequalities x>0, y>0 and 2x + 3y >12 represented on the

xy-plane In this case we draw the line x=0, y= 0 and 2x+3y=12 but the

point about the inequality signs for each equation must be considered.

the inequalities x>0, y>0 and 2x + 3y >12 represented on the

xy-plane In this case we draw the line x=0, y= 0 and 2x+3y=12 but the

point about the inequality signs for each equation must be considered.

From

the figure above, the clear region satisfy all the inequalitiesx>0,

y>0 and 2x + 3y >12, these three lines are the boundaries of the

region.

the figure above, the clear region satisfy all the inequalitiesx>0,

y>0 and 2x + 3y >12, these three lines are the boundaries of the

region.

The Solution Set of Simultaneous Linear Inequalities Graphically

Find the solution set of simultaneous linear inequalities graphically

Example 5

Draw and show the half plane represented by 8x + 2y ≥16

**Feasible Region**

**In the xy plane the region that satisfies all the given inequalities is called the**

*Definition:*

*feasible region (F.R)*Example 6

Indicate the feasible region for the inequalities 2x+3y ≥ 12 and y-x ≤ 2.

Determine the solution set of the simultaneous inequalities y + x ≥3 and x-2y ≤ 9.

Example 7

Fatuma

was given 30 shillings to buy oranges and mangoes. An orange costs

2shillings while a mango costs 3 shillings. If the number of oranges

bought is at least twice the number of mangoes, show graphically the

feasible region representing the number of ranges and mangoes she

bought, assuming that no fraction of oranges and mangoes are sold at the

market.

was given 30 shillings to buy oranges and mangoes. An orange costs

2shillings while a mango costs 3 shillings. If the number of oranges

bought is at least twice the number of mangoes, show graphically the

feasible region representing the number of ranges and mangoes she

bought, assuming that no fraction of oranges and mangoes are sold at the

market.

*Solution:-*Le

x be the number of oranges she bought and y the number of mangoes she

bought. Now the cost of x and y together is 2x + 3y shillings which must

not exceed 30 shillings. Inequalities:

x be the number of oranges she bought and y the number of mangoes she

bought. Now the cost of x and y together is 2x + 3y shillings which must

not exceed 30 shillings. Inequalities:

2x + 3y ≤30 ……… (i) and x≥2y …………….. (ii),

Also because there is no negative oranges or mangoes that can be bought,

then x≥ and y≥0 ……….. (iii)

Now

the line 2x + 3y ≤30 is the line passing through (0, 10) and (15,0) and

the line x≥2y or x – 2y ≥ 0 is the line which passes through (0,0) and

(2,1).

the line 2x + 3y ≤30 is the line passing through (0, 10) and (15,0) and

the line x≥2y or x – 2y ≥ 0 is the line which passes through (0,0) and

(2,1).

Exercise 2

For practice.

- Draw

the graph of the equation 2x – y = 7 and show which half plane is

represented by 2x – y >7 and the one represented by 2x – y <7 - On the same coordinate axes draw the graphs of the following inequalities: x + 2y ≤ 2, y-x ≤ 1 and y ≥ 0.
- Draw the graphs of y < 2x -1 and y > 3 – x on the same axes and indicate the feasible region.
- A post office has to transport 870 parcels using a lorry,

**The Objective Function**

An Objective Function from Word Problems

Form an objective function from word problems

*Linear programming components*

Any linear programming problem has the following:

- Objective
- Alternative course (s) of action which will achieve the objective.
- The available resources which are in limited supply.
- The

objective and its limitations should be able to be expressed as either

linear mathematical equations or linear inequalities. Therefore linear

programming aims at finding the best use of the available resources.

Programmingis the use of mathematical techniques in order to get the best possible solution to the problem

**Steps to be followed in solving linear programming problems;**

- Read carefully the problem, if possible do it several times.
- Use the variables like x and y to represent the resources of interest.
- Summarize

the problem by putting it in mathematical form using the variables let

in step (b) above. In this step you need to formulate the objective

function and inequalities or constraints. - Plot the constraints on a graph
- From your graph, identify the corner points.
- Use the objective function to test each corner point to find out which one gives the optimum solution.
- Make conclusion after finding or identifying the optimum point among the corner points.

**Maximum and Minimum Values**

Corner Points on the Feasible Region

Locate corner points on the feasible region

Example 8

A student has 1200 shillings to spend on exercise books. At the school

shop an exercise book costs 80shillings, and at a stationery store it

costs 120 shillings. The school shop has only 6 exercise books left and

the student wants to obtain the greatest number of exercise books

possible using the money he has. How many exercise books will the

student buy from each site?

shop an exercise book costs 80shillings, and at a stationery store it

costs 120 shillings. The school shop has only 6 exercise books left and

the student wants to obtain the greatest number of exercise books

possible using the money he has. How many exercise books will the

student buy from each site?

Therefore the student will buy 6 exercise books from each site.

Example 9

A

nutritionist prescribes a special diet for patients containing the

following number of Units of vitamins A and B per kg, of two types of

food f

nutritionist prescribes a special diet for patients containing the

following number of Units of vitamins A and B per kg, of two types of

food f

_{1}and f_{2}If

the daily minimum in take required is 120 Units of A and 70 units of B,

what is the least total mass of food a patient must have so as to have

enough of these vitamins?

the daily minimum in take required is 120 Units of A and 70 units of B,

what is the least total mass of food a patient must have so as to have

enough of these vitamins?

**Solution**

**:**

Let x be the number of kg(s) of F

_{1}that patient gets daily and y be the number of kg(s) of F_{2 }to be taken by the patient daily.Objective function: F (x, y) = (x + y) minimum

f (C) = 10 + 0 = 10

So f (B) = 6.8 is the minimum

*Therefore the least total mass of food the patient must have is 6.8 kilograms*

The Minimum and Maximum Values using the Objective Functio

Find the minimum and maximum values using the objective function

Example 10

A

farmer wants to plant coffee and potatoes. Coffee needs 3 men per

hectare while potatoes need also 3 men per hectare. He has 48 hired

laborers available. To maintain a hectare of coffee he needs 250

shillings while a hectare of potatoes costs him 100 shillings. .

farmer wants to plant coffee and potatoes. Coffee needs 3 men per

hectare while potatoes need also 3 men per hectare. He has 48 hired

laborers available. To maintain a hectare of coffee he needs 250

shillings while a hectare of potatoes costs him 100 shillings. .

Find the greatest possible land he can sow if he is prepared to use 25,000 shillings.

**Solution**

**:**

Let x be the number of hectares of coffee to be planted and y be the number of hectares of potatoes to be planted.

Objective function: f (x, y) = (x, + y) maximum

3x + 3y ≤ 48 or x + y ≤16 ………….(i)

250x + 100y≤ 25,000 Or 5x + 2y ≤ 500………(ii)

x ≥ 0 ……………………(iii)

y≥ 0 ……………………(iv)

Using the objective function f (x, y) = (x + y) maximum,

f (A) = (0 + 250) = 250

f (B) = (0+16) = 16

f (C) = (16+0) = 16 <!–EndFragment–>

f(D) = (100+0)= 100 (maximum)

Therefore the greatest possible area to be planted is 250 hectors of potatoes.

**NB**

*:*In most cases L.P problems must involve non-negativity constraints

(inequalities) that are x ≥ 0 and y ≥ 0. This is due to the fact that in

daily practice there is no use of negative quantities.

Example 11

A technical school is planning to buy two types of machines. A lather machine needs 3m

The cost of one lather machine is 25,000 shillings and that of drill

machine is 30,000 shillings. The school can spend not more than 300,000

shillings, what is the greatest number of machines the school can buy?

^{2}of floor space and a drill machine needs 2m^{2}of floor space. The total space available is 30m^{2}.The cost of one lather machine is 25,000 shillings and that of drill

machine is 30,000 shillings. The school can spend not more than 300,000

shillings, what is the greatest number of machines the school can buy?

*Solution:*Let x be the number of Lather machines and y be the number of drill machines to be bought

Objective function

*:***f(x, y) = (x + y) max**Inequalitie

*s:*3x + 2y ≤ 30.. ………………….(i)

25,000x + 30,000y ≤300,000

Or 5x + 6y ≤ 60……………………..(ii)

x ≥ 0 ……………………………….(iii)

y ≥ 0…………………… ………….(iv)

Since

the incomplete machine can’t work, then B = (8, 3) or (7, 4).That is

approximating values of x and y to the possible integers without

affecting the given inequalities or conditions.

the incomplete machine can’t work, then B = (8, 3) or (7, 4).That is

approximating values of x and y to the possible integers without

affecting the given inequalities or conditions.

Now by using the objective function,

f (A) = 0 + 10 = 10

f(B) = 7 + 4 0r f (B) = 8 + 3 = 11

f (C) = 10 + 0 = 10

f (D) = 0 + ) = 0

So f (B) gives the maximum number of machines which is 11.

Therefore the greatest number of machines that can be bought by the school is 11 machines.

Exercise 3

1. Show on a graph the feasible region for which the restrictions are:

y ≤ 2x, x≥ 6, y≥2 and 2x + 3y ≤30

From the graph at which point does:

- y – x take a maximum value?
- x + y take a maximum value?
- y – x take a maximum value?

2.

With only 20,000 shillings to spend on fish, John had the choice of

buying two types of fish. The price of a single fish type 1 was

2,500shillings and each fish of type 2 was sold at 2,000 shillings. He

wanted to buy at least four of type 1. What is the greatest number of

fish did John buy? How many of each type could he buy?

With only 20,000 shillings to spend on fish, John had the choice of

buying two types of fish. The price of a single fish type 1 was

2,500shillings and each fish of type 2 was sold at 2,000 shillings. He

wanted to buy at least four of type 1. What is the greatest number of

fish did John buy? How many of each type could he buy?

3. How many corner points does the feasible region restricted by the inequalities?

x≥0, y ≥ 0, 3x + 2y ≤ 18 and 2x + 4y ≤16 have?

Which corner point maximizes the objective function f (x, y) = 2x + 5y?